3x^(2/3)-23x^(1/3)-8=0

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Solution for 3x^(2/3)-23x^(1/3)-8=0 equation: 


x in (-oo:+oo)

3*x^(2/3)-(23*x^(1/3))-8 = 0

3*x^(2/3)-23*x^(1/3)-8 = 0

t_1 = x^(1/3)

3*t_1^2-23*t_1^1-8 = 0

3*t_1^2-23*t_1-8 = 0

DELTA = (-23)^2-(-8*3*4)

DELTA = 625

DELTA > 0

t_1 = (625^(1/2)+23)/(2*3) or t_1 = (23-625^(1/2))/(2*3)

t_1 = 8 or t_1 = -1/3

t_1 = -1/3

x^(1/3)+1/3 = 0

1*x^(1/3) = -1/3 // : 1

x^(1/3) = -1/3

( -1/3 < 0 i 1/3 in (0:1) ) => x naleu017Cy do O

t_1 = 8

x^(1/3)-8 = 0

1*x^(1/3) = 8 // : 1

x^(1/3) = 8

x^(1/3) = 8 // ^ 3

x = 512

x = 512

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